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13300010003134 = 26650005001567
BaseRepresentation
bin1100000110001010011001…
…0111110010101010111110
31202002110122120020202202001
43001202212113302222332
53220401410030100014
644141535032052514
72541615434505511
oct301424627625276
952073576222661
1013300010003134
114268558a09548
1215a976a53413a
137562548aa12a
1433da1c60cd78
15180e6cb6e974
hexc18a65f2abe

13300010003134 has 4 divisors (see below), whose sum is σ = 19950015004704. Its totient is φ = 6650005001566.

The previous prime is 13300010003087. The next prime is 13300010003167. The reversal of 13300010003134 is 43130001000331.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325002500782 + ... + 3325002500785.

It is an arithmetic number, because the mean of its divisors is an integer number (4987503751176).

Almost surely, 213300010003134 is an apocalyptic number.

13300010003134 is a deficient number, since it is larger than the sum of its proper divisors (6650005001570).

13300010003134 is an equidigital number, since it uses as much as digits as its factorization.

13300010003134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6650005001569.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13300010003134 its reverse (43130001000331), we get a palindrome (56430011003465).

The spelling of 13300010003134 in words is "thirteen trillion, three hundred billion, ten million, three thousand, one hundred thirty-four".

Divisors: 1 2 6650005001567 13300010003134