133000101001123 has 2 divisors, whose sum is σ = 133000101001124. Its totient is φ = 133000101001122.

The previous prime is 133000101001081. The next prime is 133000101001303. The reversal of 133000101001123 is 321100101000331.

It is a weak prime.

It is an emirp because it is prime and its reverse (321100101000331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133000101001123 - 2¹⁷ = 133000100870051 is a prime.

It is a super-2 number, since 2×133000101001123² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133000101001097 and 133000101001106.

It is not a weakly prime, because it can be changed into another prime (133000101031123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500050500561 + 66500050500562.

It is an arithmetic number, because the mean of its divisors is an integer number (66500050500562).

Almost surely, 2^{133000101001123} is an apocalyptic number.

133000101001123 is a deficient number, since it is larger than the sum of its proper divisors (1).

133000101001123 is an equidigital number, since it uses as much as digits as its factorization.

133000101001123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 133000101001123 its reverse (321100101000331), we get a palindrome (454100202001454).

The spelling of 133000101001123 in words is "one hundred thirty-three trillion, one hundred one million, one thousand, one hundred twenty-three".