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13300020424147 is a prime number
BaseRepresentation
bin1100000110001010011011…
…1111100010110111010011
31202002110200021212012200111
43001202212333202313103
53220401420212033042
644141540043302151
72541615622210462
oct301424677426723
952073607765614
1013300020424147
114268563886a56
1215a9771b1a957
13756256ab8502
1433da1db629d9
15180e6da2c517
hexc18a6fe2dd3

13300020424147 has 2 divisors, whose sum is σ = 13300020424148. Its totient is φ = 13300020424146.

The previous prime is 13300020424079. The next prime is 13300020424153. The reversal of 13300020424147 is 74142402000331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300020424147 is a prime.

It is not a weakly prime, because it can be changed into another prime (13300020424447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650010212073 + 6650010212074.

It is an arithmetic number, because the mean of its divisors is an integer number (6650010212074).

Almost surely, 213300020424147 is an apocalyptic number.

13300020424147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300020424147 is an equidigital number, since it uses as much as digits as its factorization.

13300020424147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 13300020424147 its reverse (74142402000331), we get a palindrome (87442422424478).

The spelling of 13300020424147 in words is "thirteen trillion, three hundred billion, twenty million, four hundred twenty-four thousand, one hundred forty-seven".