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133000311310211 is a prime number
BaseRepresentation
bin11110001111011010001100…
…010011111000011110000011
3122102220201001101001202112202
4132033122030103320132003
5114413034114143411321
61150511255521543415
740004645462102522
oct3617321423703603
9572821041052482
10133000311310211
113941812a472974
1212b004271a4b6b
135929b4c742bc7
1424bb36c5704b9
15105999b2d270b
hex78f68c4f8783

133000311310211 has 2 divisors, whose sum is σ = 133000311310212. Its totient is φ = 133000311310210.

The previous prime is 133000311310189. The next prime is 133000311310219. The reversal of 133000311310211 is 112013113000331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133000311310211 is a prime.

It is a super-2 number, since 2×1330003113102112 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133000311310219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500155655105 + 66500155655106.

It is an arithmetic number, because the mean of its divisors is an integer number (66500155655106).

Almost surely, 2133000311310211 is an apocalyptic number.

133000311310211 is a deficient number, since it is larger than the sum of its proper divisors (1).

133000311310211 is an equidigital number, since it uses as much as digits as its factorization.

133000311310211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 133000311310211 its reverse (112013113000331), we get a palindrome (245013424310542).

The spelling of 133000311310211 in words is "one hundred thirty-three trillion, three hundred eleven million, three hundred ten thousand, two hundred eleven".