Base | Representation |
---|---|
bin | 11110001111011010001100… |
… | …010011111000011110000011 |
3 | 122102220201001101001202112202 |
4 | 132033122030103320132003 |
5 | 114413034114143411321 |
6 | 1150511255521543415 |
7 | 40004645462102522 |
oct | 3617321423703603 |
9 | 572821041052482 |
10 | 133000311310211 |
11 | 3941812a472974 |
12 | 12b004271a4b6b |
13 | 5929b4c742bc7 |
14 | 24bb36c5704b9 |
15 | 105999b2d270b |
hex | 78f68c4f8783 |
133000311310211 has 2 divisors, whose sum is σ = 133000311310212. Its totient is φ = 133000311310210.
The previous prime is 133000311310189. The next prime is 133000311310219. The reversal of 133000311310211 is 112013113000331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133000311310211 is a prime.
It is a super-2 number, since 2×1330003113102112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133000311310219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500155655105 + 66500155655106.
It is an arithmetic number, because the mean of its divisors is an integer number (66500155655106).
Almost surely, 2133000311310211 is an apocalyptic number.
133000311310211 is a deficient number, since it is larger than the sum of its proper divisors (1).
133000311310211 is an equidigital number, since it uses as much as digits as its factorization.
133000311310211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 133000311310211 its reverse (112013113000331), we get a palindrome (245013424310542).
The spelling of 133000311310211 in words is "one hundred thirty-three trillion, three hundred eleven million, three hundred ten thousand, two hundred eleven".
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