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13300040140 = 225665002007
BaseRepresentation
bin11000110001011111…
…01000000111001100
31021022220101001011021
430120233220013030
5204214302241030
610035430003524
7650405322142
oct143057500714
937286331137
1013300040140
115705587012
1226b21a65a4
13133c5b4b4a
1490254d592
1552c96c97a
hex318be81cc

13300040140 has 12 divisors (see below), whose sum is σ = 27930084336. Its totient is φ = 5320016048.

The previous prime is 13300040129. The next prime is 13300040167. The reversal of 13300040140 is 4104000331.

It is a super-2 number, since 2×133000401402 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332500984 + ... + 332501023.

It is an arithmetic number, because the mean of its divisors is an integer number (2327507028).

Almost surely, 213300040140 is an apocalyptic number.

13300040140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13300040140 is an abundant number, since it is smaller than the sum of its proper divisors (14630044196).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13300040140 is a wasteful number, since it uses less digits than its factorization.

13300040140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 665002016 (or 665002014 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 13300040140 its reverse (4104000331), we get a palindrome (17404040471).

The spelling of 13300040140 in words is "thirteen billion, three hundred million, forty thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 665002007 1330004014 2660008028 3325010035 6650020070 13300040140