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1330011323133 = 3443337107711
BaseRepresentation
bin10011010110101010110…
…110100011101011111101
311201010222202221122000120
4103112222312203223331
5133242330344320013
62454555422245153
7165042630500313
oct23265266435375
94633882848016
101330011323133
1147306679a489
121959221267b9
139855b9253cc
14485313000b3
15248e3a39123
hex135aada3afd

1330011323133 has 4 divisors (see below), whose sum is σ = 1773348430848. Its totient is φ = 886674215420.

The previous prime is 1330011323131. The next prime is 1330011323177. The reversal of 1330011323133 is 3313231100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330011323133 - 21 = 1330011323131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330011323131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221668553853 + ... + 221668553858.

It is an arithmetic number, because the mean of its divisors is an integer number (443337107712).

Almost surely, 21330011323133 is an apocalyptic number.

It is an amenable number.

1330011323133 is a deficient number, since it is larger than the sum of its proper divisors (443337107715).

1330011323133 is an equidigital number, since it uses as much as digits as its factorization.

1330011323133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 443337107714.

The product of its (nonzero) digits is 1458, while the sum is 24.

Adding to 1330011323133 its reverse (3313231100331), we get a palindrome (4643242423464).

The spelling of 1330011323133 in words is "one trillion, three hundred thirty billion, eleven million, three hundred twenty-three thousand, one hundred thirty-three".

Divisors: 1 3 443337107711 1330011323133