Base | Representation |
---|---|
bin | 1100000110001010110011… |
… | …1011011100100110010011 |
3 | 1202002110221020020212012001 |
4 | 3001202230323130212103 |
5 | 3220402121210410303 |
6 | 44141554002014431 |
7 | 2541621241541542 |
oct | 301425473344623 |
9 | 52073836225161 |
10 | 13300120013203 |
11 | 4268605017761 |
12 | 15a979b347417 |
13 | 756271616c4a |
14 | 33da2d088159 |
15 | 180e7765031d |
hex | c18acedc993 |
13300120013203 has 2 divisors, whose sum is σ = 13300120013204. Its totient is φ = 13300120013202.
The previous prime is 13300120013153. The next prime is 13300120013239. The reversal of 13300120013203 is 30231002100331.
13300120013203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (30231002100331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13300120013203 - 233 = 13291530078611 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300120013273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650060006601 + 6650060006602.
It is an arithmetic number, because the mean of its divisors is an integer number (6650060006602).
Almost surely, 213300120013203 is an apocalyptic number.
13300120013203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300120013203 is an equidigital number, since it uses as much as digits as its factorization.
13300120013203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13300120013203 its reverse (30231002100331), we get a palindrome (43531122113534).
The spelling of 13300120013203 in words is "thirteen trillion, three hundred billion, one hundred twenty million, thirteen thousand, two hundred three".
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