Base | Representation |
---|---|
bin | 11110001111011011000010… |
… | …011111000110100101110001 |
3 | 122102220210101201100020011022 |
4 | 132033123002133012211301 |
5 | 114413042444334040142 |
6 | 1150511530031025225 |
7 | 40005010136524211 |
oct | 3617330237064561 |
9 | 572823351306138 |
10 | 133001220221297 |
11 | 3941855653125a |
12 | 12b0063b66b215 |
13 | 5929c65b3960c |
14 | 24bb41716a241 |
15 | 1059a00ebe6d2 |
hex | 78f6c27c6971 |
133001220221297 has 2 divisors, whose sum is σ = 133001220221298. Its totient is φ = 133001220221296.
The previous prime is 133001220221201. The next prime is 133001220221329. The reversal of 133001220221297 is 792122022100331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71076769935616 + 61924450285681 = 8430704^2 + 7869209^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133001220221297 is a prime.
It is not a weakly prime, because it can be changed into another prime (133001220221897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500610110648 + 66500610110649.
It is an arithmetic number, because the mean of its divisors is an integer number (66500610110649).
Almost surely, 2133001220221297 is an apocalyptic number.
It is an amenable number.
133001220221297 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001220221297 is an equidigital number, since it uses as much as digits as its factorization.
133001220221297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 133001220221297 in words is "one hundred thirty-three trillion, one billion, two hundred twenty million, two hundred twenty-one thousand, two hundred ninety-seven".
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