Base | Representation |
---|---|
bin | 1100000110001010110100… |
… | …0011011010011010011001 |
3 | 1202002110221101011221122201 |
4 | 3001202231003122122121 |
5 | 3220402122224221101 |
6 | 44141554114450201 |
7 | 2541621265356562 |
oct | 301425503323231 |
9 | 52073841157581 |
10 | 13300122101401 |
11 | 4268606213643 |
12 | 15a979bb93961 |
13 | 756271b98575 |
14 | 33da2d46d169 |
15 | 180e77913e01 |
hex | c18ad0da699 |
13300122101401 has 2 divisors, whose sum is σ = 13300122101402. Its totient is φ = 13300122101400.
The previous prime is 13300122101381. The next prime is 13300122101417. The reversal of 13300122101401 is 10410122100331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7104383814025 + 6195738287376 = 2665405^2 + 2489124^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300122101401 - 223 = 13300113712793 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300122101801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650061050700 + 6650061050701.
It is an arithmetic number, because the mean of its divisors is an integer number (6650061050701).
Almost surely, 213300122101401 is an apocalyptic number.
It is an amenable number.
13300122101401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300122101401 is an equidigital number, since it uses as much as digits as its factorization.
13300122101401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13300122101401 its reverse (10410122100331), we get a palindrome (23710244201732).
The spelling of 13300122101401 in words is "thirteen trillion, three hundred billion, one hundred twenty-two million, one hundred one thousand, four hundred one".
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