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13300132036577 is a prime number
BaseRepresentation
bin1100000110001010110110…
…1001010011111111100001
31202002110222001212201011012
43001202231221103333201
53220402132300132302
644141555111430305
72541621445666241
oct301425551237741
952073861781135
1013300132036577
11426861088a031
1215a97a3385395
13756273c66779
1433da308d7b21
15180e78727a52
hexc18ada53fe1

13300132036577 has 2 divisors, whose sum is σ = 13300132036578. Its totient is φ = 13300132036576.

The previous prime is 13300132036547. The next prime is 13300132036613. The reversal of 13300132036577 is 77563023100331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13267434717601 + 32697318976 = 3642449^2 + 180824^2 .

It is an emirp because it is prime and its reverse (77563023100331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300132036577 is a prime.

It is not a weakly prime, because it can be changed into another prime (13300132036547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650066018288 + 6650066018289.

It is an arithmetic number, because the mean of its divisors is an integer number (6650066018289).

Almost surely, 213300132036577 is an apocalyptic number.

It is an amenable number.

13300132036577 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300132036577 is an equidigital number, since it uses as much as digits as its factorization.

13300132036577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 238140, while the sum is 41.

The spelling of 13300132036577 in words is "thirteen trillion, three hundred billion, one hundred thirty-two million, thirty-six thousand, five hundred seventy-seven".