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1330024003423 = 9205114448773
BaseRepresentation
bin10011010110101011100…
…110111011011101011111
311201011000122210212002221
4103112223212323131133
5133242342121102143
62455000554130211
7165043143332143
oct23265346733537
94634018725087
101330024003423
11473072970365
12195926420967
1398561444c3b
1448532c81223
15248e4be12ed
hex135ab9bb75f

1330024003423 has 4 divisors (see below), whose sum is σ = 1330038544248. Its totient is φ = 1330009462600.

The previous prime is 1330024003391. The next prime is 1330024003439. The reversal of 1330024003423 is 3243004200331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330024003423 - 25 = 1330024003391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330024003723) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7132336 + ... + 7316437.

It is an arithmetic number, because the mean of its divisors is an integer number (332509636062).

Almost surely, 21330024003423 is an apocalyptic number.

1330024003423 is a deficient number, since it is larger than the sum of its proper divisors (14540825).

1330024003423 is an equidigital number, since it uses as much as digits as its factorization.

1330024003423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14540824.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 1330024003423 its reverse (3243004200331), we get a palindrome (4573028203754).

The spelling of 1330024003423 in words is "one trillion, three hundred thirty billion, twenty-four million, three thousand, four hundred twenty-three".

Divisors: 1 92051 14448773 1330024003423