Base | Representation |
---|---|
bin | 10011010110101011111… |
… | …110101110000100111001 |
3 | 11201011001002112201011101 |
4 | 103112223332232010321 |
5 | 133242400220140212 |
6 | 2455001335531401 |
7 | 165043250335561 |
oct | 23265376560471 |
9 | 4634032481141 |
10 | 1330030240057 |
11 | 473076440002 |
12 | 195928529b61 |
13 | 9856281985c |
14 | 48533a25da1 |
15 | 248e5524157 |
hex | 135abfae139 |
1330030240057 has 2 divisors, whose sum is σ = 1330030240058. Its totient is φ = 1330030240056.
The previous prime is 1330030240051. The next prime is 1330030240079. The reversal of 1330030240057 is 7500420300331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1026055547136 + 303974692921 = 1012944^2 + 551339^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330030240057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330030240051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665015120028 + 665015120029.
It is an arithmetic number, because the mean of its divisors is an integer number (665015120029).
Almost surely, 21330030240057 is an apocalyptic number.
It is an amenable number.
1330030240057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330030240057 is an equidigital number, since it uses as much as digits as its factorization.
1330030240057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 28.
Adding to 1330030240057 its reverse (7500420300331), we get a palindrome (8830450540388).
The spelling of 1330030240057 in words is "one trillion, three hundred thirty billion, thirty million, two hundred forty thousand, fifty-seven".
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