13300303033113 has 4 divisors (see below), whose sum is σ = 17733737377488. Its totient is φ = 8866868688740.

The previous prime is 13300303033093. The next prime is 13300303033141. The reversal of 13300303033113 is 31133030300331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13300303033113 - 2⁵ = 13300303033081 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13300303033613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2216717172183 + ... + 2216717172188.

It is an arithmetic number, because the mean of its divisors is an integer number (4433434344372).

Almost surely, 2^{13300303033113} is an apocalyptic number.

It is an amenable number.

13300303033113 is a deficient number, since it is larger than the sum of its proper divisors (4433434344375).

13300303033113 is an equidigital number, since it uses as much as digits as its factorization.

13300303033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4433434344374.

The product of its (nonzero) digits is 2187, while the sum is 24.

Adding to 13300303033113 its reverse (31133030300331), we get a palindrome (44433333333444).

The spelling of 13300303033113 in words is "thirteen trillion, three hundred billion, three hundred three million, thirty-three thousand, one hundred thirteen".