Base | Representation |
---|---|
bin | 1100000110001011011111… |
… | …0101100111001100110101 |
3 | 1202002111101222122020100021 |
4 | 3001202313311213030311 |
5 | 3220403010034030031 |
6 | 44142024100445141 |
7 | 2541625623305425 |
oct | 301426765471465 |
9 | 52074358566307 |
10 | 13300303033141 |
11 | 4268699362303 |
12 | 15a98306a97b1 |
13 | 7562a0507577 |
14 | 33da494ca485 |
15 | 180e88753511 |
hex | c18b7d67335 |
13300303033141 has 2 divisors, whose sum is σ = 13300303033142. Its totient is φ = 13300303033140.
The previous prime is 13300303033093. The next prime is 13300303033151. The reversal of 13300303033141 is 14133030300331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13292914943025 + 7388090116 = 3645945^2 + 85954^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300303033141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300303033151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650151516570 + 6650151516571.
It is an arithmetic number, because the mean of its divisors is an integer number (6650151516571).
Almost surely, 213300303033141 is an apocalyptic number.
It is an amenable number.
13300303033141 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300303033141 is an equidigital number, since it uses as much as digits as its factorization.
13300303033141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 13300303033141 its reverse (14133030300331), we get a palindrome (27433333333472).
The spelling of 13300303033141 in words is "thirteen trillion, three hundred billion, three hundred three million, thirty-three thousand, one hundred forty-one".
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