Base | Representation |
---|---|
bin | 1100000110001011100011… |
… | …1110000000111101011110 |
3 | 1202002111110022100111211211 |
4 | 3001202320332000331132 |
5 | 3220403024413404042 |
6 | 44142030015335034 |
7 | 2541626243525362 |
oct | 301427076007536 |
9 | 52074408314754 |
10 | 13300322013022 |
11 | 42686a9046160 |
12 | 15a9836b2147a |
13 | 7562a4421575 |
14 | 33da4bc2b2a2 |
15 | 180e8a252017 |
hex | c18b8f80f5e |
13300322013022 has 8 divisors (see below), whose sum is σ = 21764163294072. Its totient is φ = 6045600915000.
The previous prime is 13300322013001. The next prime is 13300322013029. The reversal of 13300322013022 is 22031022300331.
13300322013022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Harshad number since it is a multiple of its sum of digits (22), and also a Moran number because the ratio is a prime number: 604560091501 = 13300322013022 / (1 + 3 + 3 + 0 + 0 + 3 + 2 + 2 + 0 + 1 + 3 + 0 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 13300322012984 and 13300322013002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13300322013029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302280045729 + ... + 302280045772.
It is an arithmetic number, because the mean of its divisors is an integer number (2720520411759).
Almost surely, 213300322013022 is an apocalyptic number.
13300322013022 is a deficient number, since it is larger than the sum of its proper divisors (8463841281050).
13300322013022 is a wasteful number, since it uses less digits than its factorization.
13300322013022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 604560091514.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 13300322013022 its reverse (22031022300331), we get a palindrome (35331344313353).
The spelling of 13300322013022 in words is "thirteen trillion, three hundred billion, three hundred twenty-two million, thirteen thousand, twenty-two".
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