13300322113013 has 4 divisors (see below), whose sum is σ = 14323423814028. Its totient is φ = 12277220412000.

The previous prime is 13300322113007. The next prime is 13300322113021. The reversal of 13300322113013 is 31031122300331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8517099417649 + 4783222695364 = 2918407^2 + 2187058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13300322113013 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13300322113013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300322113613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511550850488 + ... + 511550850513.

It is an arithmetic number, because the mean of its divisors is an integer number (3580855953507).

Almost surely, 2^{13300322113013} is an apocalyptic number.

13300322113013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13300322113013 is a deficient number, since it is larger than the sum of its proper divisors (1023101701015).

13300322113013 is a wasteful number, since it uses less digits than its factorization.

13300322113013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1023101701014.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13300322113013 its reverse (31031122300331), we get a palindrome (44331444413344).

The spelling of 13300322113013 in words is "thirteen trillion, three hundred billion, three hundred twenty-two million, one hundred thirteen thousand, thirteen".