Base | Representation |
---|---|
bin | 1100000110001011100110… |
… | …1000010100101110011111 |
3 | 1202002111111002012222211221 |
4 | 3001202321220110232133 |
5 | 3220403040233312111 |
6 | 44142031053154211 |
7 | 2541626440020601 |
oct | 301427150245637 |
9 | 52074432188757 |
10 | 13300333104031 |
11 | 4268704330a86 |
12 | 15a983a78b967 |
13 | 7562a68058ac |
14 | 33da4d4b7171 |
15 | 180e8b1e3371 |
hex | c18b9a14b9f |
13300333104031 has 8 divisors (see below), whose sum is σ = 13788884867184. Its totient is φ = 12819598169280.
The previous prime is 13300333104017. The next prime is 13300333104053. The reversal of 13300333104031 is 13040133300331.
13300333104031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13300333104031 - 27 = 13300333103903 is a prime.
It is a super-2 number, since 2×133003331040312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13300333103987 and 13300333104005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13300333104731) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1954203636 + ... + 1954210441.
It is an arithmetic number, because the mean of its divisors is an integer number (1723610608398).
Almost surely, 213300333104031 is an apocalyptic number.
13300333104031 is a deficient number, since it is larger than the sum of its proper divisors (488551763153).
13300333104031 is an equidigital number, since it uses as much as digits as its factorization.
13300333104031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3908414201.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 13300333104031 its reverse (13040133300331), we get a palindrome (26340466404362).
The spelling of 13300333104031 in words is "thirteen trillion, three hundred billion, three hundred thirty-three million, one hundred four thousand, thirty-one".
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