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13300342322002 = 26650171161001
BaseRepresentation
bin1100000110001011101000…
…1011011111001101010010
31202002111111201120022112021
43001202322023133031102
53220403100113301002
644142032022522054
72541626611252261
oct301427213371522
952074451508467
1013300342322002
11426870955763a
1215a984189632a
137562a86b2508
1433da507d65d8
15180e8be14737
hexc18ba2df352

13300342322002 has 4 divisors (see below), whose sum is σ = 19950513483006. Its totient is φ = 6650171161000.

The previous prime is 13300342321999. The next prime is 13300342322051. The reversal of 13300342322002 is 20022324300331.

13300342322002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8026563268161 + 5273779053841 = 2833119^2 + 2296471^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325085580499 + ... + 3325085580502.

Almost surely, 213300342322002 is an apocalyptic number.

13300342322002 is a deficient number, since it is larger than the sum of its proper divisors (6650171161004).

13300342322002 is an equidigital number, since it uses as much as digits as its factorization.

13300342322002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6650171161003.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 13300342322002 its reverse (20022324300331), we get a palindrome (33322666622333).

The spelling of 13300342322002 in words is "thirteen trillion, three hundred billion, three hundred forty-two million, three hundred twenty-two thousand, two".

Divisors: 1 2 6650171161001 13300342322002