13300400024221 has 4 divisors (see below), whose sum is σ = 14082776496252. Its totient is φ = 12518023552192.

The previous prime is 13300400024173. The next prime is 13300400024237. The reversal of 13300400024221 is 12242000400331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9073716332121 + 4226683692100 = 3012261^2 + 2055890^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300400024221 - 2¹⁵ = 13300399991453 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13300400024192 and 13300400024201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300400024921) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391188235990 + ... + 391188236023.

It is an arithmetic number, because the mean of its divisors is an integer number (3520694124063).

Almost surely, 2^{13300400024221} is an apocalyptic number.

It is an amenable number.

13300400024221 is a deficient number, since it is larger than the sum of its proper divisors (782376472031).

13300400024221 is an equidigital number, since it uses as much as digits as its factorization.

13300400024221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 782376472030.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13300400024221 its reverse (12242000400331), we get a palindrome (25542400424552).

The spelling of 13300400024221 in words is "thirteen trillion, three hundred billion, four hundred million, twenty-four thousand, two hundred twenty-one".