13300400024173 has 2 divisors, whose sum is σ = 13300400024174. Its totient is φ = 13300400024172.

The previous prime is 13300400024159. The next prime is 13300400024237. The reversal of 13300400024173 is 37142000400331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10744248176964 + 2556151847209 = 3277842^2 + 1598797^2 .

It is an emirp because it is prime and its reverse (37142000400331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13300400024173 - 2⁵ = 13300400024141 is a prime.

It is a super-2 number, since 2×13300400024173² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300400028173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650200012086 + 6650200012087.

It is an arithmetic number, because the mean of its divisors is an integer number (6650200012087).

Almost surely, 2^{13300400024173} is an apocalyptic number.

It is an amenable number.

13300400024173 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300400024173 is an equidigital number, since it uses as much as digits as its factorization.

13300400024173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 28.

The spelling of 13300400024173 in words is "thirteen trillion, three hundred billion, four hundred million, twenty-four thousand, one hundred seventy-three".