Base | Representation |
---|---|
bin | 1100000110001100000000… |
… | …1100011101101010100011 |
3 | 1202002111202202110112112111 |
4 | 3001203000030131222203 |
5 | 3220403301432203443 |
6 | 44142050025540151 |
7 | 2541632245123153 |
oct | 301430014355243 |
9 | 52074682415474 |
10 | 13300443241123 |
11 | 4268760516675 |
12 | 15a986b644657 |
13 | 7562c358847c |
14 | 33da5dd86763 |
15 | 180e95beb69d |
hex | c18c031daa3 |
13300443241123 has 2 divisors, whose sum is σ = 13300443241124. Its totient is φ = 13300443241122.
The previous prime is 13300443241109. The next prime is 13300443241237. The reversal of 13300443241123 is 32114234400331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13300443241123 - 221 = 13300441143971 is a prime.
It is a super-2 number, since 2×133004432411232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13300443241103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650221620561 + 6650221620562.
It is an arithmetic number, because the mean of its divisors is an integer number (6650221620562).
Almost surely, 213300443241123 is an apocalyptic number.
13300443241123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300443241123 is an equidigital number, since it uses as much as digits as its factorization.
13300443241123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13300443241123 its reverse (32114234400331), we get a palindrome (45414677641454).
The spelling of 13300443241123 in words is "thirteen trillion, three hundred billion, four hundred forty-three million, two hundred forty-one thousand, one hundred twenty-three".
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