Base | Representation |
---|---|
bin | 1100000110001100000000… |
… | …1100011101101101010001 |
3 | 1202002111202202110112202221 |
4 | 3001203000030131231101 |
5 | 3220403301432210142 |
6 | 44142050025541041 |
7 | 2541632245123522 |
oct | 301430014355521 |
9 | 52074682415687 |
10 | 13300443241297 |
11 | 4268760516813 |
12 | 15a986b644781 |
13 | 7562c3588584 |
14 | 33da5dd86849 |
15 | 180e95beb767 |
hex | c18c031db51 |
13300443241297 has 2 divisors, whose sum is σ = 13300443241298. Its totient is φ = 13300443241296.
The previous prime is 13300443241271. The next prime is 13300443241391. The reversal of 13300443241297 is 79214234400331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9691522360641 + 3608920880656 = 3113121^2 + 1899716^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300443241297 - 239 = 12750687427409 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300443241237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650221620648 + 6650221620649.
It is an arithmetic number, because the mean of its divisors is an integer number (6650221620649).
Almost surely, 213300443241297 is an apocalyptic number.
It is an amenable number.
13300443241297 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300443241297 is an equidigital number, since it uses as much as digits as its factorization.
13300443241297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 435456, while the sum is 43.
The spelling of 13300443241297 in words is "thirteen trillion, three hundred billion, four hundred forty-three million, two hundred forty-one thousand, two hundred ninety-seven".
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