Base | Representation |
---|---|
bin | 1100000110001100000000… |
… | …1100101110100101000100 |
3 | 1202002111202202121001120110 |
4 | 3001203000030232211010 |
5 | 3220403301441413104 |
6 | 44142050031233020 |
7 | 2541632245532145 |
oct | 301430014564504 |
9 | 52074682531513 |
10 | 13300443310404 |
11 | 4268760563728 |
12 | 15a986b678770 |
13 | 7562c35b0b73 |
14 | 33da5dda3acc |
15 | 180e95c11e89 |
hex | c18c032e944 |
13300443310404 has 48 divisors (see below), whose sum is σ = 31068746124416. Its totient is φ = 4428570585600.
The previous prime is 13300443310387. The next prime is 13300443310411. The reversal of 13300443310404 is 40401334400331.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 197710134 + ... + 197777394.
Almost surely, 213300443310404 is an apocalyptic number.
It is an amenable number.
13300443310404 is an abundant number, since it is smaller than the sum of its proper divisors (17768302814012).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13300443310404 is a wasteful number, since it uses less digits than its factorization.
13300443310404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85276 (or 85274 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 30.
Adding to 13300443310404 its reverse (40401334400331), we get a palindrome (53701777710735).
The spelling of 13300443310404 in words is "thirteen trillion, three hundred billion, four hundred forty-three million, three hundred ten thousand, four hundred four".
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