Base | Representation |
---|---|
bin | 10011010110101100110… |
… | …100111001011010111101 |
3 | 11201011002002021020222102 |
4 | 103112230310321122331 |
5 | 133242412334123201 |
6 | 2455003004154445 |
7 | 165043512136541 |
oct | 23265464713275 |
9 | 4634062236872 |
10 | 1330044442301 |
11 | 4730834603a3 |
12 | 195931238a25 |
13 | 98565750053 |
14 | 48535881a21 |
15 | 248e68cc26b |
hex | 135acd396bd |
1330044442301 has 4 divisors (see below), whose sum is σ = 1331309947104. Its totient is φ = 1328778937500.
The previous prime is 1330044442291. The next prime is 1330044442303. The reversal of 1330044442301 is 1032444400331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1330044442301 - 234 = 1312864573117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330044442303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 632750825 + ... + 632752926.
It is an arithmetic number, because the mean of its divisors is an integer number (332827486776).
Almost surely, 21330044442301 is an apocalyptic number.
It is an amenable number.
1330044442301 is a deficient number, since it is larger than the sum of its proper divisors (1265504803).
1330044442301 is a wasteful number, since it uses less digits than its factorization.
1330044442301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1265504802.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1330044442301 its reverse (1032444400331), we get a palindrome (2362488842632).
The spelling of 1330044442301 in words is "one trillion, three hundred thirty billion, forty-four million, four hundred forty-two thousand, three hundred one".
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