133005201144131 has 4 divisors (see below), whose sum is σ = 133010944299600. Its totient is φ = 132999457988664.

The previous prime is 133005201144107. The next prime is 133005201144149. The reversal of 133005201144131 is 131441102500331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133005201144131 is a prime.

It is a super-2 number, since 2×133005201144131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133005201144094 and 133005201144103.

It is not an unprimeable number, because it can be changed into a prime (133005201144631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2871542996 + ... + 2871589313.

It is an arithmetic number, because the mean of its divisors is an integer number (33252736074900).

Almost surely, 2^{133005201144131} is an apocalyptic number.

133005201144131 is a deficient number, since it is larger than the sum of its proper divisors (5743155469).

133005201144131 is an equidigital number, since it uses as much as digits as its factorization.

133005201144131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5743155468.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 133005201144131 its reverse (131441102500331), we get a palindrome (264446303644462).

The spelling of 133005201144131 in words is "one hundred thirty-three trillion, five billion, two hundred one million, one hundred forty-four thousand, one hundred thirty-one".