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133005201144149 is a prime number
BaseRepresentation
bin11110001111011110101111…
…110001000111100101010101
3122102221011200011011001200102
4132033132233301013211111
5114413124122443103044
61150513425040023445
740005210606024245
oct3617365761074525
9572834604131612
10133005201144149
113941a209675544
1212b01370901b85
13592a44b80b979
1424bb6b3b55b25
151059b8572724e
hex78f7afc47955

133005201144149 has 2 divisors, whose sum is σ = 133005201144150. Its totient is φ = 133005201144148.

The previous prime is 133005201144107. The next prime is 133005201144203. The reversal of 133005201144149 is 941441102500331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130754811127249 + 2250390016900 = 11434807^2 + 1500130^2 .

It is an emirp because it is prime and its reverse (941441102500331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133005201144149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133005201194149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66502600572074 + 66502600572075.

It is an arithmetic number, because the mean of its divisors is an integer number (66502600572075).

Almost surely, 2133005201144149 is an apocalyptic number.

It is an amenable number.

133005201144149 is a deficient number, since it is larger than the sum of its proper divisors (1).

133005201144149 is an equidigital number, since it uses as much as digits as its factorization.

133005201144149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 133005201144149 in words is "one hundred thirty-three trillion, five billion, two hundred one million, one hundred forty-four thousand, one hundred forty-nine".