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133005201144107 is a prime number
BaseRepresentation
bin11110001111011110101111…
…110001000111100100101011
3122102221011200011011001121212
4132033132233301013210223
5114413124122443102412
61150513425040023335
740005210606024155
oct3617365761074453
9572834604131555
10133005201144107
113941a209675506
1212b01370901b4b
13592a44b80b946
1424bb6b3b55ad5
151059b85727222
hex78f7afc4792b

133005201144107 has 2 divisors, whose sum is σ = 133005201144108. Its totient is φ = 133005201144106.

The previous prime is 133005201144071. The next prime is 133005201144149. The reversal of 133005201144107 is 701441102500331.

Together with previous prime (133005201144071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133005201144107 - 222 = 133005196949803 is a prime.

It is not a weakly prime, because it can be changed into another prime (133005201944107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66502600572053 + 66502600572054.

It is an arithmetic number, because the mean of its divisors is an integer number (66502600572054).

Almost surely, 2133005201144107 is an apocalyptic number.

133005201144107 is a deficient number, since it is larger than the sum of its proper divisors (1).

133005201144107 is an equidigital number, since it uses as much as digits as its factorization.

133005201144107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

Adding to 133005201144107 its reverse (701441102500331), we get a palindrome (834446303644438).

The spelling of 133005201144107 in words is "one hundred thirty-three trillion, five billion, two hundred one million, one hundred forty-four thousand, one hundred seven".