Search a number
-
+
133010311003 is a prime number
BaseRepresentation
bin111101111100000001…
…0000100011101011011
3110201022201100212222221
41323320002010131123
54134401114423003
6141034252324511
712416055663163
oct1737002043533
9421281325887
10133010311003
1151455942369
1221940a73737
13c70975934b
14661b1d75a3
1536d72927bd
hex1ef808475b

133010311003 has 2 divisors, whose sum is σ = 133010311004. Its totient is φ = 133010311002.

The previous prime is 133010310991. The next prime is 133010311013. The reversal of 133010311003 is 300113010331.

It is a strong prime.

It is an emirp because it is prime and its reverse (300113010331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133010311003 - 217 = 133010179931 is a prime.

It is a super-2 number, since 2×1330103110032 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133010311013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505155501 + 66505155502.

It is an arithmetic number, because the mean of its divisors is an integer number (66505155502).

Almost surely, 2133010311003 is an apocalyptic number.

133010311003 is a deficient number, since it is larger than the sum of its proper divisors (1).

133010311003 is an equidigital number, since it uses as much as digits as its factorization.

133010311003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 133010311003 its reverse (300113010331), we get a palindrome (433123321334).

The spelling of 133010311003 in words is "one hundred thirty-three billion, ten million, three hundred eleven thousand, three".