Base | Representation |
---|---|
bin | 10011010110110000101… |
… | …111000100001000011001 |
3 | 11201011020122200001122102 |
4 | 103112300233010020121 |
5 | 133243031131202134 |
6 | 2455013305533145 |
7 | 165045236433515 |
oct | 23266057041031 |
9 | 4634218601572 |
10 | 1330110022169 |
11 | 473107482535 |
12 | 19594b1a41b5 |
13 | 985762019c6 |
14 | 48540473145 |
15 | 248ec53337e |
hex | 135b0bc4219 |
1330110022169 has 2 divisors, whose sum is σ = 1330110022170. Its totient is φ = 1330110022168.
The previous prime is 1330110022133. The next prime is 1330110022177. The reversal of 1330110022169 is 9612200110331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1119279361600 + 210830660569 = 1057960^2 + 459163^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330110022169 - 232 = 1325815054873 is a prime.
It is a super-2 number, since 2×13301100221692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1330110022469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665055011084 + 665055011085.
It is an arithmetic number, because the mean of its divisors is an integer number (665055011085).
Almost surely, 21330110022169 is an apocalyptic number.
It is an amenable number.
1330110022169 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330110022169 is an equidigital number, since it uses as much as digits as its factorization.
1330110022169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 1330110022169 in words is "one trillion, three hundred thirty billion, one hundred ten million, twenty-two thousand, one hundred sixty-nine".
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