Base | Representation |
---|---|
bin | 1100000110001110011101… |
… | …1001100111011000001011 |
3 | 1202002120110121011011100220 |
4 | 3001203213121213120023 |
5 | 3220411123324001303 |
6 | 44142235204001123 |
7 | 2541654453024132 |
oct | 301434731473013 |
9 | 52076417134326 |
10 | 13301101000203 |
11 | 4268a68834815 |
12 | 15a9a139901a3 |
13 | 756399928023 |
14 | 33dac3486919 |
15 | 180ed3828053 |
hex | c18e766760b |
13301101000203 has 16 divisors (see below), whose sum is σ = 17763485870976. Its totient is φ = 8853065461440.
The previous prime is 13301101000199. The next prime is 13301101000207. The reversal of 13301101000203 is 30200010110331.
13301101000203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13301101000199) and next prime (13301101000207).
It is not a de Polignac number, because 13301101000203 - 22 = 13301101000199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13301101000207) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6669000 + ... + 8430762.
It is an arithmetic number, because the mean of its divisors is an integer number (1110217866936).
Almost surely, 213301101000203 is an apocalyptic number.
13301101000203 is a deficient number, since it is larger than the sum of its proper divisors (4462384870773).
13301101000203 is a wasteful number, since it uses less digits than its factorization.
13301101000203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1765834.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13301101000203 its reverse (30200010110331), we get a palindrome (43501111110534).
The spelling of 13301101000203 in words is "thirteen trillion, three hundred one billion, one hundred one million, two hundred three", and thus it is an aban number.
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