Base | Representation |
---|---|
bin | 1100000110001110011101… |
… | …1001100111011000001111 |
3 | 1202002120110121011011101001 |
4 | 3001203213121213120033 |
5 | 3220411123324001312 |
6 | 44142235204001131 |
7 | 2541654453024136 |
oct | 301434731473017 |
9 | 52076417134331 |
10 | 13301101000207 |
11 | 4268a68834819 |
12 | 15a9a139901a7 |
13 | 756399928027 |
14 | 33dac348691d |
15 | 180ed3828057 |
hex | c18e766760f |
13301101000207 has 2 divisors, whose sum is σ = 13301101000208. Its totient is φ = 13301101000206.
The previous prime is 13301101000199. The next prime is 13301101000219. The reversal of 13301101000207 is 70200010110331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13301101000207 - 23 = 13301101000199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301101000237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650550500103 + 6650550500104.
It is an arithmetic number, because the mean of its divisors is an integer number (6650550500104).
Almost surely, 213301101000207 is an apocalyptic number.
13301101000207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301101000207 is an equidigital number, since it uses as much as digits as its factorization.
13301101000207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 13301101000207 its reverse (70200010110331), we get a palindrome (83501111110538).
The spelling of 13301101000207 in words is "thirteen trillion, three hundred one billion, one hundred one million, two hundred seven", and thus it is an aban number.
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