Base | Representation |
---|---|
bin | 1100000110001110011110… |
… | …0110110000000000110011 |
3 | 1202002120110211122002121022 |
4 | 3001203213212300000303 |
5 | 3220411130214142233 |
6 | 44142235405450055 |
7 | 2541654524214545 |
oct | 301434746600063 |
9 | 52076424562538 |
10 | 13301104443443 |
11 | 4268a6a776773 |
12 | 15a9a14b7092b |
13 | 75639a56234b |
14 | 33dac3b01695 |
15 | 180ed3ca8398 |
hex | c18e79b0033 |
13301104443443 has 2 divisors, whose sum is σ = 13301104443444. Its totient is φ = 13301104443442.
The previous prime is 13301104443391. The next prime is 13301104443467. The reversal of 13301104443443 is 34434440110331.
It is a strong prime.
It is an emirp because it is prime and its reverse (34434440110331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13301104443443 - 220 = 13301103394867 is a prime.
It is not a weakly prime, because it can be changed into another prime (13301104443043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650552221721 + 6650552221722.
It is an arithmetic number, because the mean of its divisors is an integer number (6650552221722).
Almost surely, 213301104443443 is an apocalyptic number.
13301104443443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301104443443 is an equidigital number, since it uses as much as digits as its factorization.
13301104443443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 13301104443443 its reverse (34434440110331), we get a palindrome (47735544553774).
The spelling of 13301104443443 in words is "thirteen trillion, three hundred one billion, one hundred four million, four hundred forty-three thousand, four hundred forty-three".
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