| Base | Representation |
|---|---|
| bin | 1100000110001110100000… |
| … | …1011111101111111000000 |
| 3 | 1202002120111111222210002021 |
| 4 | 3001203220023331333000 |
| 5 | 3220411140213400000 |
| 6 | 44142240354531224 |
| 7 | 2541655003151404 |
| oct | 301435013757700 |
| 9 | 52076444883067 |
| 10 | 13301114200000 |
| 11 | 4268a7522aa40 |
| 12 | 15a9a18296b14 |
| 13 | 75639c59a163 |
| 14 | 33dac5121104 |
| 15 | 180ed4a8411a |
| hex | c18e82fdfc0 |
13301114200000 has 672 divisors, whose sum is σ = 37538289395712. Its totient is φ = 4632000000000.
The previous prime is 13301114199977. The next prime is 13301114200007. The reversal of 13301114200000 is 241110331.
13301114200000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×133011142000002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301114200007) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 6888199035 + ... + 6888200965.
It is an arithmetic number, because the mean of its divisors is an integer number (55860549696).
Almost surely, 213301114200000 is an apocalyptic number.
13301114200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13301114200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18769144697856).
13301114200000 is an abundant number, since it is smaller than the sum of its proper divisors (24237175195712).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13301114200000 is a wasteful number, since it uses less digits than its factorization.
13301114200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2111 (or 2081 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13301114200000 its reverse (241110331), we get a palindrome (13301355310331).
The spelling of 13301114200000 in words is "thirteen trillion, three hundred one billion, one hundred fourteen million, two hundred thousand".
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