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133011142012523 is a prime number
BaseRepresentation
bin11110001111100100010001…
…110111101110111001101011
3122102221202000011221110000102
4132033210101313232321223
5114413223304323400043
61150520250341300015
740005511044413225
oct3617442167567153
9572852004843012
10133011142012523
1139421788088915
1212b0254a40460b
13592ab87572ab8
1424bbab8b71415
151059dd207e6b8
hex78f911deee6b

133011142012523 has 2 divisors, whose sum is σ = 133011142012524. Its totient is φ = 133011142012522.

The previous prime is 133011142012487. The next prime is 133011142012531. The reversal of 133011142012523 is 325210241110331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133011142012523 - 26 = 133011142012459 is a prime.

It is a super-2 number, since 2×1330111420125232 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133011142012583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505571006261 + 66505571006262.

It is an arithmetic number, because the mean of its divisors is an integer number (66505571006262).

Almost surely, 2133011142012523 is an apocalyptic number.

133011142012523 is a deficient number, since it is larger than the sum of its proper divisors (1).

133011142012523 is an equidigital number, since it uses as much as digits as its factorization.

133011142012523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 133011142012523 its reverse (325210241110331), we get a palindrome (458221383122854).

The spelling of 133011142012523 in words is "one hundred thirty-three trillion, eleven billion, one hundred forty-two million, twelve thousand, five hundred twenty-three".