Base | Representation |
---|---|
bin | 11110001111100100010001… |
… | …110111101110111001101011 |
3 | 122102221202000011221110000102 |
4 | 132033210101313232321223 |
5 | 114413223304323400043 |
6 | 1150520250341300015 |
7 | 40005511044413225 |
oct | 3617442167567153 |
9 | 572852004843012 |
10 | 133011142012523 |
11 | 39421788088915 |
12 | 12b0254a40460b |
13 | 592ab87572ab8 |
14 | 24bbab8b71415 |
15 | 1059dd207e6b8 |
hex | 78f911deee6b |
133011142012523 has 2 divisors, whose sum is σ = 133011142012524. Its totient is φ = 133011142012522.
The previous prime is 133011142012487. The next prime is 133011142012531. The reversal of 133011142012523 is 325210241110331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133011142012523 - 26 = 133011142012459 is a prime.
It is a super-2 number, since 2×1330111420125232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133011142012583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505571006261 + 66505571006262.
It is an arithmetic number, because the mean of its divisors is an integer number (66505571006262).
Almost surely, 2133011142012523 is an apocalyptic number.
133011142012523 is a deficient number, since it is larger than the sum of its proper divisors (1).
133011142012523 is an equidigital number, since it uses as much as digits as its factorization.
133011142012523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 133011142012523 its reverse (325210241110331), we get a palindrome (458221383122854).
The spelling of 133011142012523 in words is "one hundred thirty-three trillion, eleven billion, one hundred forty-two million, twelve thousand, five hundred twenty-three".
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