1330111530141 has 4 divisors (see below), whose sum is σ = 1773482040192. Its totient is φ = 886741020092.

The previous prime is 1330111530131. The next prime is 1330111530149. The reversal of 1330111530141 is 1410351110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330111530141 - 2¹¹ = 1330111528093 is a prime.

It is a super-2 number, since 2×1330111530141² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330111530149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221685255021 + ... + 221685255026.

It is an arithmetic number, because the mean of its divisors is an integer number (443370510048).

Almost surely, 2^{1330111530141} is an apocalyptic number.

It is an amenable number.

1330111530141 is a deficient number, since it is larger than the sum of its proper divisors (443370510051).

1330111530141 is an equidigital number, since it uses as much as digits as its factorization.

1330111530141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443370510050.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 1330111530141 its reverse (1410351110331), we get a palindrome (2740462640472).

The spelling of 1330111530141 in words is "one trillion, three hundred thirty billion, one hundred eleven million, five hundred thirty thousand, one hundred forty-one".