1330112020217 has 2 divisors, whose sum is σ = 1330112020218. Its totient is φ = 1330112020216.

The previous prime is 1330112020213. The next prime is 1330112020229. The reversal of 1330112020217 is 7120202110331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1228541692816 + 101570327401 = 1108396^2 + 318701^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330112020217 - 2² = 1330112020213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330112020192 and 1330112020201.

It is not a weakly prime, because it can be changed into another prime (1330112020213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665056010108 + 665056010109.

It is an arithmetic number, because the mean of its divisors is an integer number (665056010109).

Almost surely, 2^{1330112020217} is an apocalyptic number.

It is an amenable number.

1330112020217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330112020217 is an equidigital number, since it uses as much as digits as its factorization.

1330112020217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1330112020217 its reverse (7120202110331), we get a palindrome (8450314130548).

The spelling of 1330112020217 in words is "one trillion, three hundred thirty billion, one hundred twelve million, twenty thousand, two hundred seventeen".