1330112020219 has 8 divisors (see below), whose sum is σ = 1402028050640. Its totient is φ = 1258387003296.

The previous prime is 1330112020217. The next prime is 1330112020229. The reversal of 1330112020219 is 9120202110331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1330112020219 - 2¹ = 1330112020217 is a prime.

It is a super-2 number, since 2×1330112020219² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330112020193 and 1330112020202.

It is not an unprimeable number, because it can be changed into a prime (1330112020213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47739072 + ... + 47766925.

It is an arithmetic number, because the mean of its divisors is an integer number (175253506330).

Almost surely, 2^{1330112020219} is an apocalyptic number.

1330112020219 is a gapful number since it is divisible by the number (19) formed by its first and last digit.

1330112020219 is a deficient number, since it is larger than the sum of its proper divisors (71916030421).

1330112020219 is an equidigital number, since it uses as much as digits as its factorization.

1330112020219 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95506749.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 1330112020219 in words is "one trillion, three hundred thirty billion, one hundred twelve million, twenty thousand, two hundred nineteen".