133011202022021 has 4 divisors (see below), whose sum is σ = 134026554709344. Its totient is φ = 131995849334700.

The previous prime is 133011202022003. The next prime is 133011202022051. The reversal of 133011202022021 is 120220202110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133011202022021 - 2¹⁰ = 133011202020997 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133011202021984 and 133011202022002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133011202022051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507676343465 + ... + 507676343726.

It is an arithmetic number, because the mean of its divisors is an integer number (33506638677336).

Almost surely, 2^{133011202022021} is an apocalyptic number.

It is an amenable number.

133011202022021 is a deficient number, since it is larger than the sum of its proper divisors (1015352687323).

133011202022021 is a wasteful number, since it uses less digits than its factorization.

133011202022021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1015352687322.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 133011202022021 its reverse (120220202110331), we get a palindrome (253231404132352).

The spelling of 133011202022021 in words is "one hundred thirty-three trillion, eleven billion, two hundred two million, twenty-two thousand, twenty-one".