13301121144307 has 2 divisors, whose sum is σ = 13301121144308. Its totient is φ = 13301121144306.

The previous prime is 13301121144301. The next prime is 13301121144349. The reversal of 13301121144307 is 70344112110331.

It is a weak prime.

It is an emirp because it is prime and its reverse (70344112110331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13301121144307 - 2¹⁵ = 13301121111539 is a prime.

It is not a weakly prime, because it can be changed into another prime (13301121144301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650560572153 + 6650560572154.

It is an arithmetic number, because the mean of its divisors is an integer number (6650560572154).

Almost surely, 2^{13301121144307} is an apocalyptic number.

13301121144307 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301121144307 is an equidigital number, since it uses as much as digits as its factorization.

13301121144307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 13301121144307 its reverse (70344112110331), we get a palindrome (83645233254638).

The spelling of 13301121144307 in words is "thirteen trillion, three hundred one billion, one hundred twenty-one million, one hundred forty-four thousand, three hundred seven".