133011314004403 has 2 divisors, whose sum is σ = 133011314004404. Its totient is φ = 133011314004402.

The previous prime is 133011314004353. The next prime is 133011314004409. The reversal of 133011314004403 is 304400413110331.

It is a strong prime.

It is an emirp because it is prime and its reverse (304400413110331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133011314004403 is a prime.

It is a super-2 number, since 2×133011314004403² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133011314004409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505657002201 + 66505657002202.

It is an arithmetic number, because the mean of its divisors is an integer number (66505657002202).

Almost surely, 2^{133011314004403} is an apocalyptic number.

133011314004403 is a deficient number, since it is larger than the sum of its proper divisors (1).

133011314004403 is an equidigital number, since it uses as much as digits as its factorization.

133011314004403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 133011314004403 its reverse (304400413110331), we get a palindrome (437411727114734).

The spelling of 133011314004403 in words is "one hundred thirty-three trillion, eleven billion, three hundred fourteen million, four thousand, four hundred three".