133011341203240 has 16 divisors (see below), whose sum is σ = 299275517707380. Its totient is φ = 53204536481280.

The previous prime is 133011341203201. The next prime is 133011341203259. The reversal of 133011341203240 is 42302143110331.

It can be written as a sum of positive squares in 2 ways, for example, as 131114545676676 + 1896795526564 = 11450526^2 + 1377242^2 .

It is a junction number, because it is equal to n+sod(n) for n = 133011341203199 and 133011341203208.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1662641765001 + ... + 1662641765080.

Almost surely, 2^{133011341203240} is an apocalyptic number.

133011341203240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133011341203240 is an abundant number, since it is smaller than the sum of its proper divisors (166264176504140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133011341203240 is a wasteful number, since it uses less digits than its factorization.

133011341203240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3325283530092 (or 3325283530088 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 133011341203240 its reverse (42302143110331), we get a palindrome (175313484313571).

The spelling of 133011341203240 in words is "one hundred thirty-three trillion, eleven billion, three hundred forty-one million, two hundred three thousand, two hundred forty".