Base | Representation |
---|---|
bin | 11110001111100100100001… |
… | …111111010011001001010011 |
3 | 122102221202201000210011000222 |
4 | 132033210201333103021103 |
5 | 114413224333040301233 |
6 | 1150520333241303255 |
7 | 40005520540060460 |
oct | 3617444177231123 |
9 | 572852630704028 |
10 | 133011412431443 |
11 | 39421906798627 |
12 | 12b02604a94b2b |
13 | 592abcb5b44b0 |
14 | 24bbb02a44667 |
15 | 1059deab98898 |
hex | 78f921fd3253 |
133011412431443 has 32 divisors (see below), whose sum is σ = 167954322009600. Its totient is φ = 102540532502016.
The previous prime is 133011412431433. The next prime is 133011412431463. The reversal of 133011412431443 is 344134214110331.
It is a happy number.
It is not a de Polignac number, because 133011412431443 - 210 = 133011412430419 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133011412431433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 109012613 + ... + 110226006.
It is an arithmetic number, because the mean of its divisors is an integer number (5248572562800).
Almost surely, 2133011412431443 is an apocalyptic number.
133011412431443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133011412431443 is a deficient number, since it is larger than the sum of its proper divisors (34942909578157).
133011412431443 is a wasteful number, since it uses less digits than its factorization.
133011412431443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219238811.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 133011412431443 its reverse (344134214110331), we get a palindrome (477145626541774).
The spelling of 133011412431443 in words is "one hundred thirty-three trillion, eleven billion, four hundred twelve million, four hundred thirty-one thousand, four hundred forty-three".
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