13301144424143 has 4 divisors (see below), whose sum is σ = 13350591057960. Its totient is φ = 13251697790328.

The previous prime is 13301144424133. The next prime is 13301144424181. The reversal of 13301144424143 is 34142444110331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13301144424143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13301144424103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24723316505 + ... + 24723317042.

It is an arithmetic number, because the mean of its divisors is an integer number (3337647764490).

Almost surely, 2^{13301144424143} is an apocalyptic number.

13301144424143 is a deficient number, since it is larger than the sum of its proper divisors (49446633817).

13301144424143 is an equidigital number, since it uses as much as digits as its factorization.

13301144424143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49446633816.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 13301144424143 its reverse (34142444110331), we get a palindrome (47443588534474).

The spelling of 13301144424143 in words is "thirteen trillion, three hundred one billion, one hundred forty-four million, four hundred twenty-four thousand, one hundred forty-three".