Base | Representation |
---|---|
bin | 1100000110001110110101… |
… | …1000010001000101011011 |
3 | 1202002120201120220102121011 |
4 | 3001203231120101011123 |
5 | 3220411330013410133 |
6 | 44142253145554351 |
7 | 2541660111446503 |
oct | 301435530210533 |
9 | 52076646812534 |
10 | 13301201310043 |
11 | 426900a418009 |
12 | 15a9a414a59b7 |
13 | 7563b464986a |
14 | 33dad2918a03 |
15 | 180edc53e6cd |
hex | c18ed61115b |
13301201310043 has 2 divisors, whose sum is σ = 13301201310044. Its totient is φ = 13301201310042.
The previous prime is 13301201309983. The next prime is 13301201310049. The reversal of 13301201310043 is 34001310210331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13301201310043 - 221 = 13301199212891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13301201309996 and 13301201310023.
It is not a weakly prime, because it can be changed into another prime (13301201310049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650600655021 + 6650600655022.
It is an arithmetic number, because the mean of its divisors is an integer number (6650600655022).
Almost surely, 213301201310043 is an apocalyptic number.
13301201310043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301201310043 is an equidigital number, since it uses as much as digits as its factorization.
13301201310043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13301201310043 its reverse (34001310210331), we get a palindrome (47302511520374).
The spelling of 13301201310043 in words is "thirteen trillion, three hundred one billion, two hundred one million, three hundred ten thousand, forty-three".
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