133012110320221 has 8 divisors (see below), whose sum is σ = 145215141115104. Its totient is φ = 120827582986320.

The previous prime is 133012110320183. The next prime is 133012110320279. The reversal of 133012110320221 is 122023011210331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133012110320221 - 2⁴¹ = 130813087064669 is a prime.

It is a super-2 number, since 2×133012110320221² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133012110320192 and 133012110320201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133012110320021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4625850210 + ... + 4625878963.

It is an arithmetic number, because the mean of its divisors is an integer number (18151892639388).

Almost surely, 2^{133012110320221} is an apocalyptic number.

133012110320221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

133012110320221 is a deficient number, since it is larger than the sum of its proper divisors (12203030794883).

133012110320221 is a wasteful number, since it uses less digits than its factorization.

133012110320221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9251730491.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 133012110320221 its reverse (122023011210331), we get a palindrome (255035121530552).

The spelling of 133012110320221 in words is "one hundred thirty-three trillion, twelve billion, one hundred ten million, three hundred twenty thousand, two hundred twenty-one".