Base | Representation |
---|---|
bin | 1011000110010011110101… |
… | …0100001101001010000011 |
3 | 1121012121011012100010021012 |
4 | 2301210331110031022003 |
5 | 3044413301340414013 |
6 | 41541554524351135 |
7 | 2366432323211135 |
oct | 261447524151203 |
9 | 47177135303235 |
10 | 12203030794883 |
11 | 398530482a065 |
12 | 14510423a54ab |
13 | 6a69828b5cc6 |
14 | 3028b6401055 |
15 | 1626674bd1a8 |
hex | b193d50d283 |
12203030794883 has 2 divisors, whose sum is σ = 12203030794884. Its totient is φ = 12203030794882.
The previous prime is 12203030794847. The next prime is 12203030794891. The reversal of 12203030794883 is 38849703030221.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (38849703030221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12203030794883 - 28 = 12203030794627 is a prime.
It is not a weakly prime, because it can be changed into another prime (12203030794183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101515397441 + 6101515397442.
It is an arithmetic number, because the mean of its divisors is an integer number (6101515397442).
Almost surely, 212203030794883 is an apocalyptic number.
12203030794883 is a deficient number, since it is larger than the sum of its proper divisors (1).
12203030794883 is an equidigital number, since it uses as much as digits as its factorization.
12203030794883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 50.
The spelling of 12203030794883 in words is "twelve trillion, two hundred three billion, thirty million, seven hundred ninety-four thousand, eight hundred eighty-three".
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