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13301225503 = 20176594559
BaseRepresentation
bin11000110001101000…
…01001100000011111
31021022222121021011121
430120310021200133
5204220103204003
610035511231411
7650421360046
oct143064114037
937288537147
1013301225503
115706216655
1226b2678567
13133c90b547
1490277b55d
1552cb03cbd
hex318d0981f

13301225503 has 4 divisors (see below), whose sum is σ = 13307822080. Its totient is φ = 13294628928.

The previous prime is 13301225479. The next prime is 13301225573. The reversal of 13301225503 is 30552210331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30552210331 = 171797188843.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13301225503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13301225573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3295263 + ... + 3299296.

It is an arithmetic number, because the mean of its divisors is an integer number (3326955520).

Almost surely, 213301225503 is an apocalyptic number.

13301225503 is a deficient number, since it is larger than the sum of its proper divisors (6596577).

13301225503 is an equidigital number, since it uses as much as digits as its factorization.

13301225503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6596576.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 13301225503 its reverse (30552210331), we get a palindrome (43853435834).

The spelling of 13301225503 in words is "thirteen billion, three hundred one million, two hundred twenty-five thousand, five hundred three".

Divisors: 1 2017 6594559 13301225503