133014113431130 has 8 divisors (see below), whose sum is σ = 239425404176052. Its totient is φ = 53205645372448.

The previous prime is 133014113431099. The next prime is 133014113431141. The reversal of 133014113431130 is 31134311410331.

It can be written as a sum of positive squares in 2 ways, for example, as 106591604111041 + 26422509320089 = 10324321^2 + 5140283^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×133014113431130² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133014113431093 and 133014113431102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6650705671547 + ... + 6650705671566.

Almost surely, 2^{133014113431130} is an apocalyptic number.

133014113431130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133014113431130 is a deficient number, since it is larger than the sum of its proper divisors (106411290744922).

133014113431130 is a wasteful number, since it uses less digits than its factorization.

133014113431130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13301411343120.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 133014113431130 its reverse (31134311410331), we get a palindrome (164148424841461).

The spelling of 133014113431130 in words is "one hundred thirty-three trillion, fourteen billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred thirty".