Base | Representation |
---|---|
bin | 1100000110001111101110… |
… | …1111111011110110001011 |
3 | 1202002121100101112211201022 |
4 | 3001203323233323312023 |
5 | 3220412323223124111 |
6 | 44142333121143055 |
7 | 2541666066602603 |
oct | 301437357736613 |
9 | 52077311484638 |
10 | 13301442395531 |
11 | 4269123512114 |
12 | 15a9aaa18aa8b |
13 | 75642258a7b4 |
14 | 33db16953c03 |
15 | 1810037b22db |
hex | c18fbbfbd8b |
13301442395531 has 2 divisors, whose sum is σ = 13301442395532. Its totient is φ = 13301442395530.
The previous prime is 13301442395513. The next prime is 13301442395569. The reversal of 13301442395531 is 13559324410331.
Together with previous prime (13301442395513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13301442395531 - 218 = 13301442133387 is a prime.
It is a super-2 number, since 2×133014423955312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13301442395831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650721197765 + 6650721197766.
It is an arithmetic number, because the mean of its divisors is an integer number (6650721197766).
Almost surely, 213301442395531 is an apocalyptic number.
13301442395531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301442395531 is an equidigital number, since it uses as much as digits as its factorization.
13301442395531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 583200, while the sum is 44.
The spelling of 13301442395531 in words is "thirteen trillion, three hundred one billion, four hundred forty-two million, three hundred ninety-five thousand, five hundred thirty-one".
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