Base | Representation |
---|---|
bin | 10011010110110110010… |
… | …010001111100010010001 |
3 | 11201011111010212102120122 |
4 | 103112312102033202101 |
5 | 133243224000130001 |
6 | 2455030433320025 |
7 | 165050450022104 |
oct | 23266622174221 |
9 | 4634433772518 |
10 | 1330203130001 |
11 | 473154a96859 |
12 | 195976406015 |
13 | 9858c5a13b5 |
14 | 4854c98c73b |
15 | 249057c5b1b |
hex | 135b648f891 |
1330203130001 has 2 divisors, whose sum is σ = 1330203130002. Its totient is φ = 1330203130000.
The previous prime is 1330203129989. The next prime is 1330203130019. The reversal of 1330203130001 is 1000313020331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 921177648400 + 409025481601 = 959780^2 + 639551^2 .
It is an emirp because it is prime and its reverse (1000313020331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330203130001 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330203130051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665101565000 + 665101565001.
It is an arithmetic number, because the mean of its divisors is an integer number (665101565001).
Almost surely, 21330203130001 is an apocalyptic number.
It is an amenable number.
1330203130001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330203130001 is an equidigital number, since it uses as much as digits as its factorization.
1330203130001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 1330203130001 its reverse (1000313020331), we get a palindrome (2330516150332).
The spelling of 1330203130001 in words is "one trillion, three hundred thirty billion, two hundred three million, one hundred thirty thousand, one".
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